Doubling the wall thickness and insulation has what effect on conductive heat transfer rates?

Prepare for the Infrared Training Center Level 1 Exam. Access flashcards and multiple-choice questions with detailed explanations to help you succeed. Ace your certification today!

Multiple Choice

Doubling the wall thickness and insulation has what effect on conductive heat transfer rates?

Explanation:
Heat conduction through a flat wall depends on thickness: the thicker the wall, the greater the thermal resistance, and the smaller the heat flow for a given temperature difference. The relationship can be written as Q = k A ΔT / L, where k is the material’s thermal conductivity, A is area, ΔT is the temperature difference, and L is the wall thickness. If you double the thickness while keeping k, A, and ΔT the same, the numerator stays the same but the denominator doubles, so the heat transfer rate drops by a factor of two. Doubling insulation contributes to the same idea by increasing thermal resistance (or reducing k), further lowering Q, but the key result here is that the rate decreases by about half due to the thickness increase.

Heat conduction through a flat wall depends on thickness: the thicker the wall, the greater the thermal resistance, and the smaller the heat flow for a given temperature difference. The relationship can be written as Q = k A ΔT / L, where k is the material’s thermal conductivity, A is area, ΔT is the temperature difference, and L is the wall thickness. If you double the thickness while keeping k, A, and ΔT the same, the numerator stays the same but the denominator doubles, so the heat transfer rate drops by a factor of two. Doubling insulation contributes to the same idea by increasing thermal resistance (or reducing k), further lowering Q, but the key result here is that the rate decreases by about half due to the thickness increase.

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy